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Code (6 respuestas)
1 :
Nameless@Passing through the lobby [SG]  (*.singnet.com.sg)
: 12/02/21(fri)23:28:32
ID:GgGoUQrG0
public void shuffle ()
{ 
   int[] front = new int[cards.length/2];
   for (int k = 0; k < front.length; k++)
     front[k] = cards[k];
   int[] back = new int[cards.length/2];
   for (int k = 0; back.length; k++)
     back[k] = cards[back.length + k];
   int[] newCards = new int[cards.length]
   int j = 0;
   while (j < newCards.length)
   {
      if (k % 2 == 1)
          newCards[k] = back[cards.length/2];
      else
          newCards[k] = front [k/2];
   }
   cards = newCards;
}
 
2 :
Nameless@Passing through the lobby [CL]  (*.vtr.net)
: 12/02/21(fri)23:28:56
ID:uMh95Kz/0
hax my anus
 
3 :
Nameless@Passing through the lobby [CL]  (*.wom.cl)
: 13/02/21(sat)12:33:13
ID:9KS2F+4sa
>>1Nice code.
Wait, how do you shuffle in newCards if card.lenght is constant? Using always the same card from back[]?
 
 
In the while loop why using a variable for de conditional that always will be the same? Wouldn't be more readable to just write "newCards.length > 0"?
 
5 :
Nameless@Passing through the lobby [SG]  (*.singnet.com.sg)
: 16/02/21(tue)13:08:16
ID:G7ctNPRi0
 
6 :
Nameless@Passing through the lobby [MX]  (*.cablevision.net.mx)
: 16/02/21(tue)16:02:11
ID:V3vGq+n30
too much javascript
 
 
1 KB
 
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